Saturday, January 14, 2012

Could somebody help me with a Chemistry question?

In an acid has Ka = 3.1 x 10^-10, then what is the Kb for the conjugate base of this acid at 25�C? (Kw = 1.0 x 10^-14 at 25�C)
Posted by Jeanie Bregman at 4:26 AM

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